Analytical Functions Oracle PLSQL

SQL> CREATE TABLE employee(
  2    employee_id INTEGER,
  3    division_id CHAR(3),
  4    job_id CHAR(3),
  5    first_name VARCHAR2(10) NOT NULL,
  6    last_name VARCHAR2(10) NOT NULL,
  7    salary NUMBER(6, 0)
  8  );
Table created.
SQL>
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
  2                 values(1, 'BUS','PRE','James','Smith','800000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
  2                 values(2, 'SAL','MGR','Ron','Johnson','350000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
  2                 values(3, 'SAL','WOR','Fred','Hobbs','140000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
  2                 values(4, 'SUP','MGR','Susan','Jones','200000');
1 row created.
SQL> insert into employee (EMPLOYEE_ID,division_id,JOB_ID,FIRST_NAME,LAST_NAME,SALARY)
  2                 values(5, 'SAL','WOR','Rob','Green','350000');
1 row created.
SQL>
SQL> select * from employee;
EMPLOYEE_ID DIV JOB FIRST_NAME LAST_NAME      SALARY
----------- --- --- ---------- ---------- ----------
          1 BUS PRE James      Smith          800000
          2 SAL MGR Ron        Johnson        350000
          3 SAL WOR Fred       Hobbs          140000
          4 SUP MGR Susan      Jones          200000
          5 SAL WOR Rob        Green          350000
SQL>
SQL>
SQL>
SQL>
SQL> --An Example Query that Illustrates the Use of GROUPING_ID()
SQL>
SQL> --The following example passes division_id and job_id to GROUPING_ID(). 
Notice the output from the GROUPING_ID() function agrees with the expected returned 
values documented in the previous section:
SQL>
SQL> SELECT
  2   division_id, job_id,
  3   GROUPING(division_id) AS DIV_GRP,
  4   GROUPING(job_id) AS JOB_GRP,
  5   GROUPING_ID(division_id, job_id) AS grp_id,
  6   SUM(salary)
  7  FROM employee
  8  GROUP BY CUBE(division_id, job_id);
DIV JOB    DIV_GRP    JOB_GRP     GRP_ID SUM(SALARY)
--- --- ---------- ---------- ---------- -----------
                 1          1          3     1840000
    MGR          1          0          2      550000
    PRE          1          0          2      800000
    WOR          1          0          2      490000
BUS              0          1          1      800000
BUS PRE          0          0          0      800000
SAL              0          1          1      840000
SAL MGR          0          0          0      350000
SAL WOR          0          0          0      490000
SUP              0          1          1      200000
SUP MGR          0          0          0      200000
11 rows selected.
SQL>
SQL>
SQL>
SQL>
SQL>
SQL> drop table employee;
Table dropped.
SQL>