SQL> create table TestTable(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 Description VARCHAR2(30 BYTE)
4 )
5 /
Table created.
SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');
1 row created.
SQL> insert into TestTable (ID, Description) values('3','1234 Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');
1 row created.
SQL> insert into TestTable (ID, Description) values('5','One than another');
1 row created.
SQL> insert into TestTable (ID, Description) values('6','2003 Movie');
1 row created.
SQL> insert into TestTable (ID, Description) values('7','Start With Letters');
1 row created.
SQL>
SQL> select * from TestTable;
ID DESCRIPTION
---- ------------------------------
1 1234 5th Street
2 1 Culloden Street
3 1234 Road
4 33 Thrid Road
5 One than another
6 2003 Movie
7 Start With Letters
7 rows selected.
SQL>
SQL>
SQL>
SQL>
SQL> -- REGEXP_INSTR(description,'[aeiou][aeiou]'): Look for two consecutive vowels:
SQL>
SQL> SELECT description,
2 REGEXP_INSTR(description,'[aeiou][aeiou]')
3 where_pattern_starts
4 FROM testTable;
DESCRIPTION WHERE_PATTERN_STARTS
------------------------------ --------------------
1234 5th Street 13
1 Culloden Street 15
1234 Road 7
33 Thrid Road 11
One than another 0
2003 Movie 9
Start With Letters 0
7 rows selected.
SQL>
SQL>
SQL>
SQL> drop table TestTable;
Table dropped.
SQL>
SQL>